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| Mirrors > Home > PE Home > Th. List > specisub-P5 | |||
| Description: Specialization Theorem
with Implicit Substitution.
'𝑥' cannot occur in either '𝑡' or '𝜓'. The hypothesis is fulfilled when every free occurence of '𝑥' in '𝜑' is replaced with the term '𝑡', and every bound occurence of '𝑥' is replaced with a fresh variable (one for each quantifier). The resulting WFF is '𝜓'. After this operation, '𝑥' will not occur in '𝜓'. '𝑥' cannot occur in '𝑡' either, or it would occur in '𝜓' wherever '𝑥' was replaced. |
| Ref | Expression |
|---|---|
| specisub-P5.1 | ⊢ (𝑥 = 𝑡 → (𝜑 ↔ 𝜓)) |
| Ref | Expression |
|---|---|
| specisub-P5 | ⊢ (∀𝑥𝜑 → 𝜓) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | specisub-P5.1 | . . 3 ⊢ (𝑥 = 𝑡 → (𝜑 ↔ 𝜓)) | |
| 2 | 1 | ndbief-P3.14 179 | . 2 ⊢ (𝑥 = 𝑡 → (𝜑 → 𝜓)) |
| 3 | 2 | lemma-L5.02a 653 | 1 ⊢ (∀𝑥𝜑 → 𝜓) |
| Colors of variables: wff objvar term class |
| Syntax hints: term-obj 1 = wff-equals 6 ∀wff-forall 8 → wff-imp 10 ↔ wff-bi 104 |
| This theorem was proved from axioms: ax-L1 11 ax-L2 12 ax-L3 13 ax-MP 14 ax-GEN 15 ax-L4 16 ax-L5 17 ax-L6 18 |
| This theorem depends on definitions: df-bi-D2.1 107 df-and-D2.2 133 df-or-D2.3 145 df-true-D2.4 155 df-rcp-AND3 161 df-exists-D5.1 596 |
| This theorem is referenced by: exiisub-P5 655 qremallv-P5 656 lemma-L5.04a 667 |
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